On May 19th in sports history, one significant event took place in 1919 when Babe Ruth, playing for the Boston Red Sox, pitched a complete game shutout and also hit a home run in a 1-0 victory over the Chicago White Sox.

This game showcased Ruth's incredible versatility as a player, as he excelled both on the mound and at the plate. The home run he hit that day was a towering shot that cleared the right-field bleachers at Comiskey Park in Chicago, a feat that was rarely accomplished at the time.

Ruth's pitching performance was equally impressive, as he allowed just five hits and struck out six batters over nine innings. His shutout helped the Red Sox improve their record to 15-9 on the season, as they were defending World Series champions at the time.

Interestingly, this game took place just a few weeks before Ruth was sold to the New York Yankees, a transaction that would change the course of baseball history. The Red Sox, who had won five World Series titles with Ruth on their roster, would not win another championship until 2004, while the Yankees went on to become the most successful franchise in American sports history.

Ruth's dual dominance as a pitcher and hitter on May 19, 1919, was a testament to his unparalleled talent and helped cement his status as one of the greatest players of all time. It's a performance that has stood the test of time and remains one of the most impressive single-game achievements in the history of baseball.